/*============================================================================= This file is part of FLINT. FLINT is free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 2 of the License, or (at your option) any later version. FLINT is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with FLINT; if not, write to the Free Software Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA =============================================================================*/ /****************************************************************************** Copyright (C) 2011 Fredrik Johansson ******************************************************************************/ #include "fmpq.h" void _fmpq_add(fmpz_t rnum, fmpz_t rden, const fmpz_t p, const fmpz_t q, const fmpz_t r, const fmpz_t s) { fmpz_t g, a, b, t, u; /* Same denominator */ if (fmpz_equal(q, s)) { fmpz_add(rnum, p, r); /* Both are integers */ if (fmpz_is_one(q)) { fmpz_set(rden, q); } else { fmpz_init(g); fmpz_gcd(g, rnum, q); if (fmpz_is_one(g)) { fmpz_set(rden, q); } else { fmpz_divexact(rnum, rnum, g); fmpz_divexact(rden, q, g); } fmpz_clear(g); } return; } /* p/q is an integer */ if (fmpz_is_one(q)) { fmpz_init(t); fmpz_mul(t, p, s); fmpz_add(rnum, t, r); fmpz_set(rden, s); fmpz_clear(t); return; } /* r/s is an integer */ if (fmpz_is_one(s)) { fmpz_init(t); fmpz_mul(t, r, q); fmpz_add(rnum, t, p); fmpz_set(rden, q); fmpz_clear(t); return; } /* We want to compute p/q + r/s where the inputs are already in canonical form. If q and s are coprime, then (p*s + q*r, q*s) is in canonical form. Otherwise, let g = gcd(q, s) with q = g*a, s = g*b. Then the sum is given by ((p*b + r*a) / (a*b)) / g. As above, (p*b + r*a) / (a*b) is in canonical form, and g has no common factor with a*b. Thus we only need to reduce (p*b + r*a, g). If the gcd is 1, the reduced denominator is g*a*b = q*b. */ fmpz_init(g); fmpz_gcd(g, q, s); if (fmpz_is_one(g)) { fmpz_init(t); fmpz_init(u); fmpz_mul(t, p, s); fmpz_mul(u, q, r); fmpz_add(rnum, t, u); fmpz_mul(rden, q, s); fmpz_clear(t); fmpz_clear(u); } else { fmpz_init(a); fmpz_init(b); fmpz_init(t); fmpz_init(u); fmpz_divexact(a, q, g); fmpz_divexact(b, s, g); fmpz_mul(t, p, b); fmpz_mul(u, r, a); fmpz_add(rnum, t, u); fmpz_gcd(t, rnum, g); if (fmpz_is_one(t)) { fmpz_mul(rden, q, b); } else { fmpz_divexact(rnum, rnum, t); fmpz_divexact(g, q, t); fmpz_mul(rden, g, b); } fmpz_clear(a); fmpz_clear(b); fmpz_clear(t); fmpz_clear(u); } fmpz_clear(g); } void fmpq_add(fmpq_t res, const fmpq_t op1, const fmpq_t op2) { _fmpq_add(fmpq_numref(res), fmpq_denref(res), fmpq_numref(op1), fmpq_denref(op1), fmpq_numref(op2), fmpq_denref(op2)); }