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- Again, we can do pattern matching on lists.
- \begin{haskellcode}
- listLen :: [Integer] -> Integer
- listLen [] = 0
- listLen (x:xs) = 1 + listLen xs
- \end{haskellcode}
- \pause
- We can also nest pattern matching:
- \begin{haskellcode}
- sumEveryTwo :: [Integer] -> [Integer]
- sumEveryTwo [] = 0
- sumEveryTwo (x:[]) = [x]
- sumEveryTwo (x:(y:zs)) = (x + y) : sumEveryTwo zs
- \end{haskellcode}
- Note that \hinline{(x:(y:zs))} may also be written as \hinline{(x:y:zs)}.
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