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@ -2,7 +2,7 @@ To cut the story short, the abstract solution looks like this:
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\begin{haskellcode}
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fold :: b -> (a -> b -> b) -> [a] -> b
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fold z f [] = z
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fold z f (x:xs) = f x (fold z f xs)
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fold z f (x:xs) = x `f` (fold z f xs)
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\end{haskellcode}
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Whoa! What's going on here?\\
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Let's see...
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