hasufell
899afc7287
The old code in fact increased the complexity to O(n^2), because we applied 'elem' which is O(n) to every element of xs. Instead we compare (in case of partitioning against Y) the y-value of every element of xs with the y-value of the pivot which tells us if x lies within ys. |
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ConvexHull | ||
KDTree | ||
PolygonIntersection | ||
QuadTree |